# Find Numbers With Even Number of Digits Solution

Given an array `nums` of integers, return how many of them contain an even number of digits.

Example 1:

```Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
```

Example 2:

```Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
```

Constraints:

• `1 <= nums.length <= 500`
• `1 <= nums[i] <= 105`
``````class Solution {
public int findNumbers(int[] nums) {
int count = 0,i=0;
for (; i < nums.length; i++) {
String str = Integer.toString(nums[i]);
if (str.length() % 2 == 0)
count++;
}
return count;
}
}``````

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