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Find Numbers With Even Number of Digits Solution

Given an array nums of integers, return how many of them contain an even number of digits.

Example 1:

Input: nums = [12,345,2,6,7896]
Output: 2
Explanation: 
12 contains 2 digits (even number of digits). 
345 contains 3 digits (odd number of digits). 
2 contains 1 digit (odd number of digits). 
6 contains 1 digit (odd number of digits). 
7896 contains 4 digits (even number of digits). 
Therefore only 12 and 7896 contain an even number of digits.

Example 2:

Input: nums = [555,901,482,1771]
Output: 1 
Explanation: 
Only 1771 contains an even number of digits.

Constraints:

  • 1 <= nums.length <= 500
  • 1 <= nums[i] <= 105
class Solution {
    public int findNumbers(int[] nums) {
    int count = 0,i=0;
        for (; i < nums.length; i++) {
            String str = Integer.toString(nums[i]);
            if (str.length() % 2 == 0)
                count++;
        }
        return count;
    }
}

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